When light propagates through a material medium of relative permittivity $\varepsilon_{r}$ and relative permeability $\mu_{r}$,the velocity of light,$v$,is given by: ($c$ = velocity of light in vacuum)

  • A
    $v=\sqrt{\frac{\mu_{r}}{\varepsilon_{r}}}$
  • B
    $v=\sqrt{\frac{\varepsilon_{r}}{\mu_{r}}}$
  • C
    $v=\frac{c}{\sqrt{\varepsilon_{r}\mu_{r}}}$
  • D
    $v=c$

Explore More

Similar Questions

If the frequency of an electromagnetic wave is $60 \text{ MHz}$ and it travels in air along the $z$-direction,then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other. The wavelength of the wave (in $\text{m}$) is:

An electromagnetic wave has a frequency of $3 \text{ MHz}$ in free space. When this wave passes through a medium with a relative permittivity $\varepsilon_r = 4.0$,its frequency will be:

What is the dimension of $\frac{1}{\mu_0 \varepsilon_0}$? ($\mu_0 =$ magnetic permeability and $\varepsilon_0 =$ permittivity of free space)

The electric field part of an electromagnetic wave in a medium is represented by:
$E_x = 0;$
$E_y = 2.5 \, \text{N/C} \cos \left[ \left( 2\pi \times 10^6 \, \text{rad/s} \right) t - \left( \pi \times 10^{-2} \, \text{rad/m} \right) x \right];$
$E_z = 0.$
The wave is:

Difficult
View Solution

If the direction of propagation of an electromagnetic wave is along the $z$-axis,then the directions of the electric field $(E)$ and magnetic field $(B)$ are:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo