When light travels from air to water,then fro | vedclass

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(A) The refractive index of medium $2$ with respect to medium $1$ is defined as $_1{n_2} = \frac{n_2}{n_1}$.For a series of media,the product of refra

Vedclass · Accepted Answer

$_a{n_w} 	imes {_w}{n_{gl}} 	imes {_{gl}}{n_{gas}} 	imes {_{gas}}{n_a} = 1$

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(A) The refractive index of medium $2$ with respect to medium $1$ is defined as $_1{n_2} = \frac{n_2}{n_1}$.For a series of media,the product of refractive indices is:$_a{n_w} 	imes {_w}{n_{gl}} 	imes {_{gl}}{n_{gas}} 	imes {_{gas}}{n_a} = \left( \frac{n_w}{n_a} ight) 	imes \left( \frac{n_{gl}}{n_w} ight) 	imes \left( \frac{n_{gas}}{n_{gl}} ight) 	imes \left( \frac{n_a}{n_{gas}} ight) = 1$.Thus,the product of the refractive indices for a closed loop of media returns to the initial medium is equal to $1$.

When light travels from air to water,then from water to glass,then from glass to $CO_2$ gas,and finally back to air,the relation between their refractive indices is given by:

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