When photons of energy $hf$ fall on an aluminium plate (of work function $E_0$),photoelectrons of maximum kinetic energy $K$ are ejected. If the frequency of radiation is doubled,the maximum kinetic energy of the ejected photoelectrons will be:

  • A
    $K+ hf$
  • B
    $K+ E_0$
  • C
    $2K$
  • D
    $K+ hf$

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