When the angle of inclination of an inclined | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $1$. When the object slides down with uniform velocity,the net force is zero. This implies the component of gravity $mg \sin 	heta$ is balanced b

Vedclass · Accepted Answer

slides down the inclined plane and reaches the ground with velocity less than $u$.

Vedclass · Answer

(B) $1$. When the object slides down with uniform velocity,the net force is zero. This implies the component of gravity $mg \sin 	heta$ is balanced by the kinetic friction $f_k = \mu_k N = \mu_k mg \cos 	heta$. Thus,$\mu_k = 	an 	heta$.$2$. When the object is pushed up with velocity $u$,it experiences a retardation $a_{up} = g \sin 	heta + \mu_k g \cos 	heta$. Since $\mu_k = 	an 	heta$,$a_{up} = g \sin 	heta + (	an 	heta) g \cos 	heta = 2g \sin 	heta$.$3$. After stopping,the object slides down. The acceleration while sliding down is $a_{down} = g \sin 	heta - \mu_k g \cos 	heta$. Since $\mu_k = 	an 	heta$,$a_{down} = g \sin 	heta - g \sin 	heta = 0$. Wait,this implies uniform velocity. Let's re-evaluate: the kinetic friction acts opposite to motion. When sliding down,$a_{down} = g \sin 	heta - \mu_k g \cos 	heta = 0$. The object will slide down with the same velocity it had at the start of the descent. Since it started from rest at the top,it will slide down with uniform velocity. However,the question implies it reaches the ground. The energy lost due to friction during the upward journey is $W_f = f_k 	imes d = (\mu_k mg \cos 	heta) d$. During the downward journey,the same energy is lost. By work-energy theorem,the final kinetic energy $K_f = K_i + W_{gravity} - W_{friction}$. Since $W_{gravity}$ is the same for both paths and $W_{friction}$ is the same,the final velocity will be less than $u$ due to energy dissipation.

When the angle of inclination of an inclined plane is $\theta$,an object slides down with uniform velocity. If the same object is pushed up with an initial velocity $u$ on the same inclined plane,it goes up the plane and stops at a certain distance on the plane. Thereafter,the body:

Similar Questions

$A$ disc arranged in a vertical plane has two grooves of the same length directed along the vertical chord $AB$ and the chord $CD$ as shown in the figure. Particles slide down along $AB$ and $CD$ starting from rest. The ratio of the time $t_{AB}/t_{CD}$ is

Find the reading of the weighing machine $(WM)$ in the following case. The system is in equilibrium.

$A$ homogeneous rectangular brick lies on a rough inclined plane of very small inclination. Which half part of the brick exerts a greater contact force on the plane?

$A$ block of mass $10 \, kg$ is moving down an inclined plane with a constant velocity of $10 \, m/s$. The angle of inclination is $37^{\circ}$. The coefficient of kinetic friction between the inclined plane and the block is:

$A$ particle is projected up along a rough inclined plane of inclination $45^{\circ}$ with the horizontal. If the coefficient of friction is $0.5$,the acceleration is ($g=$ Acceleration due to gravity).

Vedclass Test Series

Exam Paper Generator

Online Exam Module