When the object is self-luminous,the resolving power of a microscope is given by the expression

If an object kept at the least distance of distinct vision is just resolved with light of wavelength $500 \ nm$ and a pupil of diameter $1 \ mm$,at what distance will the object be just resolved if the wavelength is $400 \ nm$ and the pupil diameter is $0.8 \ mm$ (in $cm$)?

By increasing the aperture of the objective lens,how do the wavelength of light,the focal length of the objective lens,and the resolving power of an astronomical telescope change,respectively?

$A$ telescope is used to observe two objects at a distance of $z = 10 \ km$ which are $s = 0.12 \ m$ apart and illuminated by light of wavelength $\lambda = 600 \ nm$. Estimate the diameter of the objective lens of the telescope if it can just resolve the two objects. Assume diameter $D >> \lambda$ and separation between objects $s << z$. The answer is in $cm$.

An astronomical telescope has a large aperture to

If the numerical aperture $(NA)$ of a microscope is increased,then its: