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(A) The resolving power $(RP)$ of an astronomical telescope is given by the formula: $RP = \frac{a}{1.22 \lambda}$,where $a$ is the aperture (diameter

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is not affected,is not affected,increases.

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(A) The resolving power $(RP)$ of an astronomical telescope is given by the formula: $RP = \frac{a}{1.22 \lambda}$,where $a$ is the aperture (diameter) of the objective lens and $\lambda$ is the wavelength of light.$1$. The wavelength of light $(\lambda)$ depends on the source and is independent of the aperture of the objective lens. Thus,it is not affected.$2$. The focal length $(f)$ of the objective lens is a property determined by its curvature and refractive index,which does not change by simply increasing the aperture (diameter). Thus,it is not affected.$3$. From the formula $RP \propto a$,we see that the resolving power is directly proportional to the aperture $a$. Therefore,increasing the aperture increases the resolving power.Hence,the correct sequence is: is not affected,is not affected,increases.

By increasing the aperture of the objective lens,how do the wavelength of light,the focal length of the objective lens,and the resolving power of an astronomical telescope change,respectively?

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