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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K.E.)_{\max}$ of emitted photoelectrons is given by:$(K.E.)_{\max} = h

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decreases.

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(D) According to Einstein's photoelectric equation,the maximum kinetic energy $(K.E.)_{\max}$ of emitted photoelectrons is given by:$(K.E.)_{\max} = h
u - \phi_0$Where:$h
u$ is the energy of the incident photon.$\phi_0$ is the work function of the metal.From the equation,it is clear that $(K.E.)_{\max}$ is inversely proportional to the work function $\phi_0$ for a constant incident frequency $
u$.Therefore,if the work function $\phi_0$ increases,the maximum kinetic energy $(K.E.)_{\max}$ decreases.

When the work function of a metal increases,the maximum kinetic energy of the emitted photoelectrons:

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