Where is maximum acceleration and zero accele | vedclass

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Question

(B) For a particle executing $SHM$,the acceleration $a$ is given by the formula $a = -\omega^2 x$,where $\omega$ is the angular frequency and $x$ is t

Vedclass · Accepted Answer

Maximum at extreme positions,zero at mean position

Vedclass · Answer

(B) For a particle executing $SHM$,the acceleration $a$ is given by the formula $a = -\omega^2 x$,where $\omega$ is the angular frequency and $x$ is the displacement from the mean position.At the mean position,$x = 0$,so the acceleration $a = -\omega^2(0) = 0$. Thus,acceleration is zero at the mean position.At the extreme positions,the displacement $x$ is equal to the amplitude $A$ (i.e.,$x = \pm A$). The magnitude of acceleration is $|a| = |-\omega^2(\pm A)| = \omega^2 A$,which is the maximum value.Therefore,acceleration is maximum at the extreme positions and zero at the mean position.

Where is maximum acceleration and zero acceleration of a particle executing $SHM$?

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