(C) The electronic configuration of $O_{2}^{+}$ is $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^

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$O_{2}^{+}$ ion is diamagnetic.

(C) The electronic configuration of $O_{2}^{+}$ is $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} = \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{1}$.Since $O_{2}^{+}$ ion has $15$ electrons,it contains one unpaired electron in the $\pi^{*}$ orbital.Therefore,it is paramagnetic in nature,making the statement in option $C$ incorrect.

Class 11 Chemistry Chemical Bonding and Molecular Structure Molecular orbital theory

Medium

Which amongst the following is an incorrect statement?

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A
$C_{2}$ molecule has four electrons in its two degenerate $\pi$ molecular orbitals.
B
$H_{2}^{+}$ ion has one electron.
C
$O_{2}^{+}$ ion is diamagnetic.
D
The bond orders of $O_{2}^{+}, O_{2}, O_{2}^{-}$ and $O_{2}^{2-}$ are $2.5, 2, 1.5$ and $1,$ respectively.