Which of the following statements is correct?

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(B) Let us analyze each option:$A$: $(CH_3)_3SiOH$ is more acidic than $(CH_3)_3COH$ because the $Si-O$ bond is more polar and the $Si$ atom can stabi

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In trisilyl phosphine,$p\pi -d\pi$ backbonding takes place

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(B) Let us analyze each option:$A$: $(CH_3)_3SiOH$ is more acidic than $(CH_3)_3COH$ because the $Si-O$ bond is more polar and the $Si$ atom can stabilize the conjugate base through $p\pi -d\pi$ backbonding. Thus,$A$ is incorrect.$B$: In trisilyl phosphine,$N(SiH_3)_3$ (or $P(SiH_3)_3$),the lone pair on the central atom is donated into the empty $d$-orbitals of $Si$,which is $p\pi -d\pi$ backbonding. This is correct.$C$: In $SO_2$,there are two $S=O$ bonds. Each $S=O$ bond consists of one $\sigma$ bond and one $d\pi -p\pi$ bond. Thus,there are two $d\pi -p\pi$ bonds. This is also correct.$D$: In $H_2SO_4$,the central $S$ atom is $sp^3$ hybridized. The fraction of $s$-character is $1/4 = 0.25$. This is also correct.Note: In many competitive chemistry contexts,multiple statements may be technically correct depending on the specific curriculum focus. However,$B$ is a classic textbook example of $p\pi -d\pi$ bonding.

Column $I$	Column $II$
$(A)$ $B_2$	$(p)$ Paramagnetic
$(B)$ $N_2$	$(q)$ Undergoes oxidation
$(C)$ $O_2^{-}$	$(r)$ Undergoes reduction
$(D)$ $O_2$	$(s)$ Bond order $\geq 2$
	$(t)$ Mixing of '$s$' and '$p$' orbitals

Similar Questions

State whether the bond order increases or decreases when $O_2$ changes to $O_2^+$ and when $N_2$ changes to $N_2^+$.

Which of the following species,$O_2^-$ or $O_2^{2-}$,has a higher bond order?

Identify the set containing isoelectronic species.

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