Which amongst the following is the most stabl | vedclass

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Question

(B) The correct answer is $(B)$ $CH_3-C^+(CH_3)_2$.Carbocation stability is determined by the inductive effect $(+I)$ and hyperconjugation.$CH_3-C^+(C

Vedclass · Accepted Answer

$CH_3-C^+(CH_3)_2$

Vedclass · Answer

(B) The correct answer is $(B)$ $CH_3-C^+(CH_3)_2$.Carbocation stability is determined by the inductive effect $(+I)$ and hyperconjugation.$CH_3-C^+(CH_3)_2$ is a $3^\circ$ carbocation,which is stabilized by the electron-donating effect of three methyl groups.$CH_3-CH^+(CH_3)$ is a $2^\circ$ carbocation,$CH_3-CH_2^+$ is a $1^\circ$ carbocation,and $CH_3^+$ is a methyl carbocation.Stability order: $3^\circ > 2^\circ > 1^\circ > 	ext{methyl}$.

Label	Carbocation
$1$	$CH_3-CH^+-CH_3$
$2$	$CH_3^+$
$3$	$(CH_3)_3C^+$
$4$	$CH_3-CH_2^+$

Which amongst the following is the most stable carbocation?

Similar Questions

What is the correct order of stability for $1^\circ, 2^\circ, 3^\circ$ carbocations and benzyl carbocation?

Arrange the following carbocations in the increasing order of stability with respect to their labels:
Label Carbocation
$1$ $CH_3-CH^+-CH_3$
$2$ $CH_3^+$
$3$ $(CH_3)_3C^+$
$4$ $CH_3-CH_2^+$

In the above reaction,the left-hand side and right-hand side rings are named as '$A$' and '$B$' respectively. They undergo ring expansion. The correct statement for this process is:

What is the order of stability of carbon free radicals among ${3^\circ}$,${2^\circ}$,${1^\circ}$,and $\mathop C\limits^\bullet {H_3}$?

The correct order of stability of the following carbocations is:

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