The correct order of stability of the followi | vedclass

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Question

(A) The stability of carbocations is determined by the presence of electron-donating groups attached to the positively charged carbon atom. $(a)$ $(CH

Vedclass · Accepted Answer

$a > d > b > c$

Vedclass · Answer

(A) The stability of carbocations is determined by the presence of electron-donating groups attached to the positively charged carbon atom. $(a)$ $(CH_3)_2C^+-NHCH_3$: The nitrogen atom has a lone pair which provides strong resonance stabilization ($+M$ effect) to the carbocation. $(d)$ $(CH_3)_2C^+-OCH_3$: The oxygen atom has lone pairs which provide resonance stabilization ($+M$ effect). Since nitrogen is less electronegative than oxygen,it donates its lone pair more effectively,making $(a)$ more stable than $(d)$. $(b)$ $(CH_3)_2C^+-CH_2CH_3$: This is a tertiary carbocation stabilized by the inductive effect $(+I)$ and hyperconjugation of the alkyl groups. $(c)$ $(CH_3)_2CH^+$: This is a secondary carbocation,which is less stable than the tertiary carbocation $(b)$. Thus,the order of stability is $(a) > (d) > (b) > (c)$.

The correct order of stability of the following carbocations is:

Similar Questions

State whether the following statements are True or False:
$(i)$ $CH_3-CH_2^+$ is more stable than $CH_3^+$
$(ii)$ $CH_3-CH_2^+$ is less stable than $CH_3^+$
$(iii)$ $(CH_3)_3C^+$ is less stable than $CH_3^+$
$(iv)$ $(CH_3)_3C^+$ is more stable than $CH_3^+$

In which pair is the second ion more stable than the first?

With a change in hybridisation of the carbon bearing the charge,the stability of a carbanion increases in the order:

Which of the following represents the incorrect order of stability?

The most stable carbocation among the following is:

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