Which complex compound possesses sp^3d^2 hybr | vedclass

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(A) In $[Fe(Cl)_6]^{3-}$,the oxidation state of $Fe$ is $+3$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Since $Cl^-$ is a weak field l

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$[Fe(Cl)_6]^{3-}$

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(A) In $[Fe(Cl)_6]^{3-}$,the oxidation state of $Fe$ is $+3$. The electronic configuration of $Fe^{3+}$ is $[Ar] 3d^5$. Since $Cl^-$ is a weak field ligand,it does not cause pairing of electrons in the $3d$ orbitals. Therefore,the $3d$ electrons remain unpaired,and the complex utilizes the $4s$,$4p$,and $4d$ orbitals for hybridization,resulting in $sp^3d^2$ hybridization. This is an outer orbital complex. In contrast,$[Fe(CN)_6]^{3-}$,$[Fe(CN)_6]^{4-}$,and $[Fe(NH_3)_6]^{3+}$ involve strong field ligands (or specific electronic conditions) that lead to $d^2sp^3$ hybridization (inner orbital complexes).

$LIST-I$	$LIST-II$
$P. dsp^2$	$1. [FeF_6]^{4-}$
$Q. sp^3$	$2. [Ti(H_2O)_3Cl_3]$
$R. sp^3d^2$	$3. [Cr(NH_3)_6]^{3+}$
$S. d^2sp^3$	$4. [FeCl_4]^{2-}$
	$5. Ni(CO)_4$
	$6. [Ni(CN)_4]^{2-}$

Which complex compound possesses $sp^3d^2$ hybridisation?

Similar Questions

Match each set of hybrid orbitals from $LIST-I$ with complex(es) given in $LIST-II$. The correct option is

$LIST-I$ $LIST-II$

$P. dsp^2$ $1. [FeF_6]^{4-}$

$Q. sp^3$ $2. [Ti(H_2O)_3Cl_3]$

$R. sp^3d^2$ $3. [Cr(NH_3)_6]^{3+}$

$S. d^2sp^3$ $4. [FeCl_4]^{2-}$

$5. Ni(CO)_4$

$6. [Ni(CN)_4]^{2-}$

Which of the following is an outer orbital complex? (Atomic numbers: $Mn = 25, Fe = 26, Co = 27, Ni = 28$)

Aluminium chloride in acidified aqueous solution forms a complex $A$,in which hybridisation of $Al$ is $B$. What are $A$ and $B$,respectively?

Which one of the following is square planar in structure and has diamagnetic property?

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