Which gas among the following contains the ma | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \

Vedclass · Accepted Answer

$16.0 \ g$ of $CH_{4}$

Vedclass · Answer

(B) The number of molecules is directly proportional to the number of moles $(n = \frac{	ext{mass}}{	ext{molar mass}})$. $I. \ n_{Ar} = \frac{13.3 \ g}{39.9 \ g \ mol^{-1}} = 0.33 \ mol$ $II. \ n_{O_{2}} = \frac{24.0 \ g}{32 \ g \ mol^{-1}} = 0.75 \ mol$ $III. \ n_{CO_{2}} = \frac{11 \ g}{44 \ g \ mol^{-1}} = 0.25 \ mol$ $IV. \ n_{CH_{4}} = \frac{16.0 \ g}{16 \ g \ mol^{-1}} = 1.0 \ mol$ Since $CH_{4}$ has the maximum number of moles $(1.0 \ mol)$,it contains the maximum number of molecules.

Which gas among the following contains the maximum number of molecules at $STP$? (Molar masses in $g \ mol^{-1}$: $CO_{2}=44, Ar=39.9, CH_{4}=16, O_{2}=32$)

Similar Questions

The weight of $112 \ cm^3$ of $CH_4$ gas at $STP$ is ...... $g$.

$A$ gaseous mixture of $O_2$ and $CH_4$ are in the ratio $1: 4$ by mass. Find the ratio of their molecules.

The largest number of molecules is in

Which of the following contains the maximum number of atoms?

Three $1 \ L$ flasks contain $N_2$,$Ne$,and $O_3$ gases respectively. At the same temperature and pressure,find the ratio of the total number of atoms present.

Vedclass Test Series

Exam Paper Generator

Online Exam Module