Which graph is not a straight line for an ide | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For an ideal gas,the equation is $PV = nRT$.$A$. $P$ vs $\frac{1}{V}$ at constant $T$ & $n$: Since $P = (nRT) 	imes \frac{1}{V}$,this is a linear

Vedclass · Accepted Answer

$P$ vs $T^2$ (at constant $V$ & $n$)

Vedclass · Answer

(C) For an ideal gas,the equation is $PV = nRT$.$A$. $P$ vs $\frac{1}{V}$ at constant $T$ & $n$: Since $P = (nRT) 	imes \frac{1}{V}$,this is a linear equation of the form $y = mx$ passing through the origin. It is a straight line.$B$. $PV$ vs $V^2$ at constant $T$ & $n$: Since $PV = nRT$ (a constant),the graph of $PV$ vs $V^2$ is a horizontal line parallel to the $V^2$ axis. It is a straight line.$C$. $P$ vs $T^2$ at constant $V$ & $n$: From $P = (\frac{nR}{V})T$,we see that $P \propto T$. Therefore,$P$ vs $T^2$ is a parabolic curve,not a straight line.$D$. $\log\ P$ vs $\log\ (V^2)$ at constant $T$ & $n$: Since $PV = k$,$P = k V^{-1}$. Taking log on both sides,$\log\ P = \log\ k - \log\ V$. Since $\log\ (V^2) = 2 \log\ V$,we have $\log\ P = \log\ k - \frac{1}{2} \log\ (V^2)$. This is a linear equation of the form $y = mx + c$. It is a straight line.

Which graph is not a straight line for an ideal gas?

Similar Questions

Which of the following does not represent Charles's Law?

Select the correct statement for the equation $PV = nRT$.

$A$ gas has a volume of $3.4 \ L$ at $25^{\circ} C$. What is the final temperature if the volume increases to $10.2 \ L$ at constant pressure (in $K$)?

Explain: Gay-Lussac's Law.

The density of a gas at $27\,^oC$ and $1\, atm$ is $d$. At constant pressure,which of the following temperatures will result in a gas density of $0.75\, d$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module