Which of the following has the minimum freezi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The depression in freezing point is a colligative property,which depends on the van't Hoff factor $(i)$.$i$ for $NaCl$ is $2$ $(Na^+ + Cl^-)$.$i$

Vedclass · Accepted Answer

One molal $CaCl_2$ solution

Vedclass · Answer

(C) The depression in freezing point is a colligative property,which depends on the van't Hoff factor $(i)$.$i$ for $NaCl$ is $2$ $(Na^+ + Cl^-)$.$i$ for $KCl$ is $2$ $(K^+ + Cl^-)$.$i$ for $CaCl_2$ is $3$ $(Ca^{2+} + 2Cl^-)$.$i$ for urea is $1$ (non-electrolyte).Since the depression in freezing point $\Delta T_f = i 	imes K_f 	imes m$,the solution with the highest $i$ value will have the maximum depression in freezing point,resulting in the minimum freezing point.Therefore,$CaCl_2$ has the minimum freezing point.

Which of the following has the minimum freezing point?

Similar Questions

Calculate the depression in the freezing point of water when $10 \ g$ of $CH_3CH_2CHClCOOH$ is added to $250 \ g$ of water. $K_a = 1.4 \times 10^{-3}$,$K_f = 1.86 \ K \ kg \ mol^{-1}$

$0.01 \ M$ solutions of glucose,phenol,and potassium chloride were prepared in water. The boiling points of these solutions follow the order:

The freezing point depression of a $0.01 \ m$ aqueous solution of $[Pt(NH_3)_4Cl_4]$ is $0.0054^\circ C$. If $K_f$ for water is $1.80 \ K \ kg \ mol^{-1}$,what is the correct formula for the complex?

Which of the following $0.1 \, M$ aqueous solutions has the lowest freezing point?

Vedclass Test Series

Exam Paper Generator

Online Exam Module