Which is the correct order of ionisation ener | vedclass

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Question

(C) The ionisation energy $(IE)$ is inversely proportional to the size of the atom or ion $(IE \propto \frac{1}{	ext{size}})$. For neutral atoms,$O$

Vedclass · Accepted Answer

$O > S > O^{-} > S^{-}$

Vedclass · Answer

(C) The ionisation energy $(IE)$ is inversely proportional to the size of the atom or ion $(IE \propto \frac{1}{	ext{size}})$. For neutral atoms,$O$ has a smaller size than $S$,so $IE(O) > IE(S)$. For anions,$O^{-}$ has a smaller size than $S^{-}$,so $IE(O^{-}) > IE(S^{-})$. Comparing neutral atoms and anions,neutral atoms have a much higher $IE$ than their corresponding anions because removing an electron from a negatively charged species is easier than from a neutral one. Thus,the correct order is $O > S > O^{-} > S^{-}$.

Which is the correct order of ionisation energy?

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