Which is the correct sequence in the followin | vedclass

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(A) $(F)$; As the size of the halogen atom increases,the back-bonding tendency from halogen to $Si$ decreases,increasing the Lewis acidity. Thus,the c

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(A) $(F)$; As the size of the halogen atom increases,the back-bonding tendency from halogen to $Si$ decreases,increasing the Lewis acidity. Thus,the correct order is $SiF_4 $(b)$ $(T)$; $NH_3$ has the highest melting point due to intermolecular $H$-bonding. The rest follow the order of molecular weight: $SbH_3 > AsH_3 > PH_3$.$(c)$ $(F)$; The boiling point order is $PH_3 $(d)$ $(T)$; The dipole moment order is $NH_3 > SbH_3 > AsH_3 > PH_3$ due to the high electronegativity of $N$ and the lone pair contribution.

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