(C) The stability of coordination complexes increases as we move down a group in the periodic table because the $4d$ and $5d$ orbitals are more extend

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Stability order: $[Co(H_2O)_6]^{3+} > [Rh(H_2O)_6]^{3+}$

(C) The stability of coordination complexes increases as we move down a group in the periodic table because the $4d$ and $5d$ orbitals are more extended than $3d$ orbitals,leading to better overlap with ligands.Therefore,the stability order is $[Co(H_2O)_6]^{3+} Option $C$ is the incorrect observation.

Class 12 Chemistry Coordination Compounds Complexes and complex stability

Which is the incorrect observation?

A
For the complex,$[CoF_6]^{3-}$,$F^{-}$ is a weak-field ligand,so that $\Delta_{oct} < P$ (electron-pairing energy) and is thus a high spin complex.
B
For the complex,$[Co(NH_3)_6]^{3+}$,$NH_3$ is a strong-field ligand,so that $\Delta_{oct} > P$ and thus a low spin complex.
C
Stability order: $[Co(H_2O)_6]^{3+} > [Rh(H_2O)_6]^{3+}$
D
Greater the ionic charge on the central metal ion,the greater the value of $\Delta$ $(CFSE)$.