Which of the following amines forms a clear s | vedclass

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(D) The reaction with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary ami

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$CH_{3}NH_{2}$

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(D) The reaction with benzene sulphonyl chloride (Hinsberg's reagent) is used to distinguish between primary,secondary,and tertiary amines.Primary amines $(R-NH_{2})$ react with benzene sulphonyl chloride to form $N$-alkylbenzene sulphonamide,which contains an acidic hydrogen atom attached to the nitrogen.This acidic hydrogen makes the product soluble in excess of potassium hydroxide $(KOH)$,resulting in a clear solution.Secondary amines $(R_{2}NH)$ form $N,N$-dialkylbenzene sulphonamides,which lack an acidic hydrogen and are insoluble in $KOH$.Tertiary amines $(R_{3}N)$ do not react with benzene sulphonyl chloride.Among the given options,$CH_{3}NH_{2}$ is a primary amine,so it forms a clear solution.

$LIST$-$I$	$LIST$-$II$
$A$. Cyclohexanol	$I$. Hinsberg's reagent
$B$. Cyclohexylamine	$II$. Phthalein dye test
$C$. Cyclohexanecarbaldehyde	$III$. Lucas test
$D$. Phenol	$IV$. Tollen's test

Which of the following amines forms a clear solution when treated with benzene sulphonyl chloride and excess of potassium hydroxide?

Similar Questions

The amine that reacts with Hinsberg's reagent to give an alkali-insoluble product is:

Match the $LIST$-$I$ with $LIST$-$II$:

$LIST$-$I$ $LIST$-$II$

$A$. Cyclohexanol $I$. Hinsberg's reagent

$B$. Cyclohexylamine $II$. Phthalein dye test

$C$. Cyclohexanecarbaldehyde $III$. Lucas test

$D$. Phenol $IV$. Tollen's test

The test used to distinguish between primary,secondary,and tertiary amines is:

Which one of the products of the following reactions does not react with Hinsberg reagent to form sulphonamide?

Which of the following amine$(s)$ show$(s)$ positive carbylamine test?
$A. CH_3CH_2NH_2$
$B. (CH_3)_2NH$
$C. CH_3NH_2$
$D. (CH_3)_3N$
$E. C_6H_5NH_2$
Choose the correct answer from the options given below:

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