Which of the following can show geometrical i | vedclass

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(A) For a molecule to show geometrical isomerism,the atoms or groups attached to each carbon atom of the double bond must be different.$(a)$ $CH_3-CH=

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$a, b, d$

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(A) For a molecule to show geometrical isomerism,the atoms or groups attached to each carbon atom of the double bond must be different.$(a)$ $CH_3-CH=N-OH$: The $C=N$ bond has different groups on both sides ($H$ and $CH_3$ on $C$; $OH$ and lone pair on $N$),so it shows geometrical isomerism.$(b)$ The exocyclic double bond in the cyclopropane ring has different groups on the terminal carbon ($H$ and $CH_3$). The ring itself also has different substituents ($Cl$ and $Cl$ at different positions),allowing for geometrical isomerism.$(c)$ $1,2-dimethylcyclohexene$: The double bond is within a six-membered ring. The two carbons of the double bond are attached to identical $CH_3$ groups (or rather,the ring constraints and symmetry make it unable to show cis-trans isomerism in this specific configuration),so it does not show geometrical isomerism.$(d)$ $CH_2=CH-CH=CH-Ph$: This is a conjugated diene. The internal $C=C$ bond has different groups on each carbon ($H$ and $CH=CH_2$ on one side; $H$ and $Ph$ on the other),so it shows geometrical isomerism.Thus,$(a)$,$(b)$,and $(d)$ show geometrical isomerism.

Which of the following can show geometrical isomerism?

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