The total number of stereoisomers of the comp | vedclass

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Question

(C) The compound $1$-bromo-$3$-chlorocyclobutane exhibits geometric isomerism due to the substituents at positions $1$ and $3$ on the cyclobutane ring

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(C) The compound $1$-bromo-$3$-chlorocyclobutane exhibits geometric isomerism due to the substituents at positions $1$ and $3$ on the cyclobutane ring.
These two substituents can be on the same side of the ring ($cis$-isomer) or on opposite sides of the ring ($trans$-isomer).
Both the $cis$ and $trans$ forms possess a plane of symmetry,meaning they are achiral and do not exhibit optical activity.
Thus,there are exactly $2$ stereoisomers for this compound.

The total number of stereoisomers of the compound $1$-bromo-$3$-chlorocyclobutane is:

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