Which of the following complexes has a shape | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the shape,we analyze the hybridization of each complex:$1$. $[Zn(NH_3)_4]^{2+}$: $Zn^{2+}$ has a $d^{10}$ configuration. It undergoes

Vedclass · Accepted Answer

$[Cu(NH_3)_4]^{2+}$

Vedclass · Answer

(D) To determine the shape,we analyze the hybridization of each complex:$1$. $[Zn(NH_3)_4]^{2+}$: $Zn^{2+}$ has a $d^{10}$ configuration. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$2$. $[Ni(CO)_4]$: $Ni$ is in the $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing of electrons. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$3$. $[Cu(CN)_4]^{3-}$: $Cu^+$ has a $d^{10}$ configuration. It undergoes $sp^3$ hybridization,resulting in a tetrahedral geometry.$4$. $[Cu(NH_3)_4]^{2+}$: $Cu^{2+}$ has a $d^9$ configuration. It undergoes $dsp^2$ hybridization,resulting in a square planar geometry.Thus,$[Cu(NH_3)_4]^{2+}$ has a square planar shape,while the others are tetrahedral.

Which of the following complexes has a shape different from the others?

Similar Questions

The number of unpaired electrons in the complex $[CoF_6]^{3-}$ is ...... . (Atomic number of $Co = 27$)

The geometries of the ammonia complexes of $Ni^{2+}$,$Pt^{2+}$ and $Zn^{2+}$,respectively,are

In the crystal of $CuSO_4 \cdot 5H_2O$,the copper atom is coordinated by:

The structure of iron pentacarbonyl,$Fe(CO)_5$,is ................. .

How many unpaired electrons are present in the cobalt ion in the $+3$ oxidation state prior to hybridization in the $[CoF_6]^{3-}$ complex ion?

Vedclass Test Series

Exam Paper Generator

Online Exam Module