Which of the following complexes has dsp^2 hy | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$ ($3d^8$ configuration).$CN^-$ is a strong field ligand,which causes the pairing of electro

Vedclass · Accepted Answer

$[Ni(CN)_4]^{2-}$

Vedclass · Answer

(B) In $[Ni(CN)_4]^{2-}$,the central metal ion is $Ni^{2+}$ ($3d^8$ configuration).$CN^-$ is a strong field ligand,which causes the pairing of electrons in the $3d$ orbitals.This leaves one $3d$ orbital,one $4s$ orbital,and two $4p$ orbitals vacant,which undergo $dsp^2$ hybridisation to form a square planar geometry.Conversely,$[Ni(CO)_4]$ and $[NiCl_4]^{2-}$ involve $sp^3$ hybridisation,resulting in a tetrahedral geometry.

Which of the following complexes has $dsp^2$ hybridisation?

Similar Questions

Which statement is incorrect regarding the complex $[HgI_3]^{-}$?

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

Which of the following complexes is diamagnetic and square planar?

Which of the following configurations will show an outer orbital octahedral complex?

The species which has four unpaired electrons is

Vedclass Test Series

Exam Paper Generator

Online Exam Module