Which of the following compounds is most basi | vedclass

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(B) The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.In $C_6H_5-CH_2NH_2$ (benz

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$C_6H_5-CH_2NH_2$ (benzylamine)

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(B) The basicity of an amine depends on the availability of the lone pair of electrons on the nitrogen atom for protonation.In $C_6H_5-CH_2NH_2$ (benzylamine),the lone pair on the nitrogen atom is localised because the $-NH_2$ group is attached to an $sp^3$ hybridized carbon atom,which is not directly attached to the benzene ring.In the other compounds ($p$-nitroaniline,acetanilide,and aniline),the lone pair on the nitrogen atom is delocalized over the benzene ring due to resonance,making it less available for donation.Therefore,benzylamine is the most basic compound among the given options.

Which of the following compounds is most basic?

Similar Questions

$A$ primary amine,$RNH_2$ can be reacted with $CH_3-X$ to get a secondary amine,$RNHCH_3$,but the disadvantage is that $3^o$ amine and quaternary ammonium salts are also obtained as side products. Can you suggest a method where $RNH_2$ forms only $2^o$ amine?

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