Which of the following electrolytes will have | vedclass

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(A) According to the Hardy-Schulze law,the flocculating value is inversely proportional to the valency of the coagulating ion,i.e.,$	ext{Flocculating

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$NaCl$

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(A) According to the Hardy-Schulze law,the flocculating value is inversely proportional to the valency of the coagulating ion,i.e.,$	ext{Flocculating value} \propto \frac{1}{z}$,where $z$ is the valency of the coagulating ion.$Fe(OH)_3$ is a positively charged sol,so it is coagulated by negative ions.The negative ions present in the given electrolytes are:$A) Cl^-$ (valency = $1$)$B) S^{2-}$ (valency = $2$)$C) PO_4^{3-}$ (valency = $3$)$D) SO_4^{2-}$ (valency = $2$)Since $Cl^-$ has the lowest valency $(z=1)$,it will have the maximum flocculation value. Therefore,$NaCl$ has the maximum flocculation value.

Which of the following electrolytes will have the maximum flocculation value for $Fe(OH)_3$ sol?

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