Which of the following electronic configurati | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Ionization energy decreases down a group and increases across a period. Alkali metals have the lowest ionization energy in their respective period

Vedclass · Accepted Answer

$1s^2 2s^2 2p^6 3s^1$

Vedclass · Answer

(D) Ionization energy decreases down a group and increases across a period. Alkali metals have the lowest ionization energy in their respective periods due to their large atomic size and stable noble gas core configuration plus one valence electron $(ns^1)$. Among the given options,$1s^2 2s^2 2p^6 3s^1$ represents Sodium $(Na)$,which is an alkali metal and has the lowest ionization energy compared to the other elements listed (which are non-metals or metalloids in the second period).

Which of the following electronic configurations represents the element with the lowest ionization energy?

Similar Questions

Amongst the following elements,the highest ionization energy is

In which of the following electronic configurations will there be a large difference between the second and third ionization energy?

When the first ionization energies are plotted against atomic number,the peaks are occupied by:

The ionization energy of hydrogen is:

Find the incorrect comparison of second ionisation energy.

Vedclass Test Series

Exam Paper Generator

Online Exam Module