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(C) In the complex $[Cr(NH_3)_6]Cl_3$,the oxidation state of $Cr$ is $+3$. The electronic configuration of $Cr^{3+}$ is $[Ar]3d^3$. Since $NH_3$ is a

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The complex is an outer orbital complex.

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(C) In the complex $[Cr(NH_3)_6]Cl_3$,the oxidation state of $Cr$ is $+3$. The electronic configuration of $Cr^{3+}$ is $[Ar]3d^3$. Since $NH_3$ is a ligand,it forms an octahedral complex using $d^2sp^3$ hybridization. Because it uses $(n-1)d$ orbitals ($3d$ orbitals),it is classified as an inner orbital complex,not an outer orbital complex. Therefore,the statement that it is an outer orbital complex is wrong.

Which of the following facts about the complex $[Cr(NH_3)_6]Cl_3$ is wrong?

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