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(A) The rate of $S_{N}2$ reaction depends on the steric hindrance and the nature of the leaving group.Steric hindrance follows the order: $primary > s

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$I$

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(A) The rate of $S_{N}2$ reaction depends on the steric hindrance and the nature of the leaving group.Steric hindrance follows the order: $primary > secondary > tertiary$.In the given options:$(I)$ is $1$-iodobutane (primary alkyl halide with a good leaving group $I^-$).$(II)$ is $1$-chlorobutane (primary alkyl halide with a poorer leaving group $Cl^-$).$(III)$ is chlorocyclohexane (secondary alkyl halide).$(IV)$ is cyclohexylmethyl chloride (primary alkyl halide,but with steric hindrance from the cyclohexane ring near the reaction center).Comparing $(I)$ and $(II)$,both are primary,but $I^-$ is a better leaving group than $Cl^-$,making $(I)$ more reactive.Comparing $(I)$ and $(IV)$,$(I)$ is less sterically hindered than $(IV)$.Therefore,$(I)$ undergoes $S_{N}2$ reaction at the fastest rate.

Which of the following haloalkanes would undergo $S_{N}2$ reaction at the fastest rate?

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