Which of the following has the longest C-O bo | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In metal carbonyl complexes,the metal-carbon bond is formed by the donation of lone pairs from $CO$ to the metal,and back-bonding occurs from the

Vedclass · Accepted Answer

$[Fe(CO)_4]^{2-}$

Vedclass · Answer

(A) In metal carbonyl complexes,the metal-carbon bond is formed by the donation of lone pairs from $CO$ to the metal,and back-bonding occurs from the metal $d$-orbitals to the empty $\pi^*$ antibonding orbitals of $CO$. As the negative charge on the metal carbonyl complex increases,the electron density on the metal increases,which enhances the back-donation of electrons into the $\pi^*$ antibonding orbitals of $CO$. This increases the population of the antibonding orbitals,which weakens the $C-O$ bond and increases its bond length. Comparing the complexes: $1. [Mn(CO)_6]^+$: Metal has a positive charge,least back-bonding. $2. [Ni(CO)_4]$: Neutral complex. $3. [Co(CO)_4]^-$: Negative charge,more back-bonding. $4. [Fe(CO)_4]^{2-}$: Highest negative charge,maximum back-bonding. Therefore,$[Fe(CO)_4]^{2-}$ has the longest $C-O$ bond length. The order is $[Mn(CO)_6]^+ < [Ni(CO)_4] < [Co(CO)_4]^- < [Fe(CO)_4]^{2-}$.

Which of the following has the longest $C-O$ bond length? (Free $C-O$ bond length in $CO$ is $1.128 \ \mathring{A}$.)

Similar Questions

The Wilkinson catalyst,used for the hydrogenation of alkenes as a homogeneous catalyst,contains $......$.

Explain the bonding in metal carbonyls.

Discuss the nature of bonding in metal carbonyls.

In Zeise's salt,the central metal atom acts as:

Select the correct statement about the anionic part of Zeise's salt,$K[Pt(\eta^2 - C_2H_4)Cl_3]$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module