Which of the following involves the transfer | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine the number of electrons transferred,we calculate the change in the oxidation number $(O.N.)$ of the central metal atom.For option $A$

Vedclass · Accepted Answer

$MnO_4^- 	o Mn^{2+}$

Vedclass · Answer

(A) To determine the number of electrons transferred,we calculate the change in the oxidation number $(O.N.)$ of the central metal atom.For option $A$: In $MnO_4^-$,the $O.N.$ of $Mn$ is $+7$. In $Mn^{2+}$,the $O.N.$ is $+2$. The change is $|7 - 2| = 5$ electrons.For option $B$: In $CrO_4^{2-}$,the $O.N.$ of $Cr$ is $+6$. In $Cr^{3+}$,the $O.N.$ is $+3$. The change is $3$ electrons.For option $C$: In $MnO_4^{2-}$,the $O.N.$ of $Mn$ is $+6$. In $MnO_2$,the $O.N.$ of $Mn$ is $+4$. The change is $2$ electrons.For option $D$: In $Cr_2O_7^{2-}$,the $O.N.$ of $Cr$ is $+6$. In $Cr^{3+}$,the $O.N.$ is $+3$. Since there are two $Cr$ atoms,the total change is $2 	imes (6 - 3) = 6$ electrons.Thus,the reaction involving the transfer of $5$ electrons is $MnO_4^- 	o Mn^{2+}$.

Which of the following involves the transfer of five electrons?

Similar Questions

The oxidation number of $N$ in $NH_3$ is:

Assign the oxidation number to the underlined element in each of the following species:
$1$. $K_2\underline{Mn}O_4$
$2$. $Ca\underline{O}_2$
$3$. $Na\underline{B}H_4$
$4$. $KAl(\underline{S}O_4)_2 \cdot 12H_2O$

What are the oxidation states of three $Br$ atoms in $Br_3O_8$ molecule?

What is the oxidation state of iodine in $I_2Cl_6$?

What is the oxidation number of $Cl$ in $CaOCl_2$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module