Which of the following is a low-spin complex?

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) low-spin complex is formed when the crystal field splitting energy $(\Delta_o)$ is greater than the pairing energy $(P)$. This typically occurs wi

Vedclass · Accepted Answer

$[Fe(NH_3)_6]^{3+}$

Vedclass · Answer

(D) low-spin complex is formed when the crystal field splitting energy $(\Delta_o)$ is greater than the pairing energy $(P)$. This typically occurs with strong field ligands like $NH_3$ and $CN^-$. In $[Fe(NH_3)_6]^{3+}$,the central metal ion is $Fe^{3+}$ ($d^5$ configuration). $NH_3$ is a strong field ligand,which causes the electrons to pair up in the $t_{2g}$ orbitals,resulting in a low-spin configuration $(t_{2g}^5 e_g^0)$. In contrast,$[Ni(NH_3)_6]^{2+}$ $(d^8)$ and $[Cr(NH_3)_6]^{3+}$ $(d^3)$ do not exhibit low-spin/high-spin variations due to their specific electronic configurations. $[Ti(H_2O)_6]^{3+}$ $(d^1)$ also does not exhibit spin states. Therefore,$[Fe(NH_3)_6]^{3+}$ is the correct answer.

Similar Questions

Assign $A, B, C, D$ from the given type of reaction.
$CuSO_4 + NH_3$ (Excess) $\longrightarrow [Cu(NH_3)_4]^{2+}$

With which of the following will ammonia $NOT$ form a complex compound?

Amongst the following,the most stable complex is:
$(i)$ $[Fe(H_2O)_6]^{3+}$
$(ii)$ $[Fe(NH_3)_6]^{3+}$
$(iii)$ $[Fe(C_2O_4)_3]^{3-}$
$(iv)$ $[FeCl_6]^{3-}$

Which complex is most stable? Where $k_d =$ Dissociation constant.

When concentrated sulphuric acid is added slowly to a solution of ferrous sulphate containing nitrate ion,a brown coloured ring is formed. The composition of the ring is

Vedclass Test Series

Exam Paper Generator

Online Exam Module