Which of the following is correctly matched w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let's analyze each option:$A)$ Heat of combustion is inversely proportional to the stability of the alkene. More substituted alkenes are more stab

Vedclass · Accepted Answer

$2,3	ext{-dimethylbut-2-ene} < 2	ext{-methylbut-2-ene} < 	ext{but-2-ene}$ (Heat of combustion)

Vedclass · Answer

(A) Let's analyze each option:$A)$ Heat of combustion is inversely proportional to the stability of the alkene. More substituted alkenes are more stable and have lower heat of combustion. The order should be: $ ext{but-2-ene} > 2 ext{-methylbut-2-ene} > 2,3 ext{-dimethylbut-2-ene}$. Thus,the given order is correct.$B)$ Boiling point increases with molecular weight and decreases with branching. $ ext{Methanol} (CH_3OH)$ has the lowest boiling point. Between $ ext{butan-1-ol}$ and $ ext{butan-2-ol}$,$ ext{butan-1-ol}$ has a higher boiling point due to less branching. The correct order is: $ ext{Methanol} $C)$ The stability of the carbocation is increased by the $+M$ effect of the oxygen atom. The closer the oxygen atom is to the positive charge,the more stable the cation. The correct order is: $4 ext{-oxocyclohexyl cation} $D)$ Bond length of $C=C$ increases as the double bond character decreases due to resonance. In $CH_3O-CH=CH_2$,the lone pair on oxygen participates in resonance,giving the $C=C$ bond more single bond character,thus increasing its length. The correct order is: $CH_2=CH_2 < CH_3-CH=CH_2 < CH_3O-CH=CH_2$.

Which of the following is correctly matched with their property?

Similar Questions

Which of the following is a wrong representation of electron displacement?

Identify the functional group that has electron donating inductive effect.

Which of the following represents the correct order of stability?

The most stable carbocation among the following is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module