Which of the following is a wrong representat | vedclass

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(C) In resonance or conjugation,electron displacement occurs from a region of high electron density (like a lone pair or a $\pi$ bond) to an adjacent

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(C) In resonance or conjugation,electron displacement occurs from a region of high electron density (like a lone pair or a $\pi$ bond) to an adjacent single bond to form a new $\pi$ bond.In options $A$,$B$,and $D$,the lone pairs on $N$,$O$,and $Cl$ respectively are conjugated with the benzene ring,so moving a lone pair to form a double bond with the ring carbon is a correct representation of resonance.In option $C$,the cyano group $(-C \equiv N)$ is attached to the benzene ring. The carbon of the cyano group is $sp$ hybridized and already forms a triple bond with nitrogen. Moving the $\pi$ electrons of the $C \equiv N$ bond towards the ring carbon would result in a pentavalent carbon atom,which is chemically impossible. Therefore,this is a wrong representation.

List-$I$	List-$II$
$(A)$ Resonance	$(I)$ $C=C + H^+ \rightarrow C^+-C-H$
$(B)$ Inductive effect	$(II)$ $H-CH_2-CH_2^+ \leftrightarrow H-CH_2=CH_2^+$
$(C)$ Electromeric effect	$(III)$ $C_6H_6$
$(D)$ Hyperconjugation	$(IV)$ $CH_3-Z \rightarrow CH_3^- + Z^+$
	$(V)$ $CH_3-CH_2-CH_2Cl$

Which of the following is a wrong representation of electron displacement?

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