Which of the following is more stable than th | vedclass

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions al

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Methyl anion

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions already possess a negative charge,the presence of electron-donating groups increases the electron density on the carbon atom,which destabilizes the carbanion. Therefore,the stability order is: $	ext{Methyl anion} > 	ext{Ethyl anion} > 	ext{Isobutyl anion} > t-	ext{Butyl anion}$. Among the given options,the methyl anion $(CH_3^-)$ is the most stable because it has no electron-donating alkyl groups attached to the negatively charged carbon.

Which of the following is more stable than the remaining three?

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