Which of the following is not arranged in the correct sequence?
- A$MO, M_2O_3, MO_2, M_2O_5$ - Decreasing basic nature
- B$Sc, V, Cr, Mn$ - Increasing number of oxidation states
- C$d^5, d^3, d^1, d^4$ - Increasing magnetic moment
- D$Mn^{2+}, Fe^{2+}, Cr^{2+}, Co^{2+}$ - Decreasing stability
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Given below are two statements:
Statement $I$: The number of pairs among $[Ti^{4+}, V^{2+}], [V^{2+}, Mn^{2+}], [Mn^{2+}, Fe^{3+}]$ and $[V^{2+}, Cr^{2+}]$ in which both ions are coloured is $3$.
Statement $II$: The number of pairs among $[La^{3+}, Yb^{2+}], [Lu^{3+}, Ce^{4+}]$ and $[Ac^{3+}, Lr^{3+}]$ ions in which both are diamagnetic is $3$.
In the light of the above statements, choose the correct option from the options given below:
Statement $I$: The number of pairs among $[Ti^{4+}, V^{2+}], [V^{2+}, Mn^{2+}], [Mn^{2+}, Fe^{3+}]$ and $[V^{2+}, Cr^{2+}]$ in which both ions are coloured is $3$.
Statement $II$: The number of pairs among $[La^{3+}, Yb^{2+}], [Lu^{3+}, Ce^{4+}]$ and $[Ac^{3+}, Lr^{3+}]$ ions in which both are diamagnetic is $3$.
In the light of the above statements, choose the correct option from the options given below:
Which of the following represents the correct order of stability for the given oxidation states?
Easy
View SolutionWhich of the following will give a green hydrated ion?
Easy
View SolutionWhich of the following orders is correct?
Medium
View SolutionSelect the correct option.
Easy
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