Which of the following will give a green hydrated ion?

Match the items in Column-$I$ with the items in Column-$II$.

Column-$I$	Column-$II$
$(1)$ General electronic configuration of $d$-block elements	$(A)$ Transition elements
$(2)$ $d$-block elements	$(B)$ $(n-1)d^{1-10}ns^{1-2}$
$(3)$ Groups $3$ to $12$	$(C)$ $Z = 58$ to $71$
$(4)$ Lanthanoid elements	$(D)$ Last electron enters $d$-orbital

The number of statement$(s)$ correct from the following for copper (atomic number $29$) is/are $...$
$(A) \ Cu(II)$ complexes are always paramagnetic
$(B) \ Cu(I)$ complexes are generally colourless
$(C) \ Cu(I)$ is easily oxidized
$(D)$ In Fehling solution,the active reagent has $Cu(II)$

Match the following:

List-$I$	List-$II$
$A$. Oxidation state of $V$ in $VOCl_2$	$I$. $0$
$B$. Number of unpaired electrons in $MnO_4^{2-}$ ion	$II$. $1$
$C$. Number of unpaired electrons in $[NiCl_4]^{2-}$ ion	$III$. $5$
$D$. This oxidation state is exhibited by all lanthanide ions	$IV$. $3$
	$V$. $4$
	$VI$. $2$

The correct answer is:

Select the correct option.

Identify the correct option:
$(I)\ AgCl$ is not soluble in $H_2O$ but soluble in $KCN$.
$(II)\ Zn$ when reacts with cold v.v. dil $HNO_3$ gives $NH_4NO_3$.
$(III)\ CuSO_4$ reacts with $KI$ to form $Cu_2I_2 + K_2SO_4$.
$(IV)\ CuSO_4 \cdot 5H_2O \xrightarrow{1000\,^oC}$ The gases liberated are $SO_2$ and $O_2$.