Which of the following is not correctly match | vedclass

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(B) Let us analyze each option:$A$. $[MnCl_4]^{2-}$: $Mn^{2+}$ is $d^5$. $Cl^-$ is a weak field ligand,so it is high spin. $CFSE = [0.6 	imes n_{eg}

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$[Pt(NH_3)ClBr(py)]$ Shows both $G.I$ and optical isomerism

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(B) Let us analyze each option:$A$. $[MnCl_4]^{2-}$: $Mn^{2+}$ is $d^5$. $Cl^-$ is a weak field ligand,so it is high spin. $CFSE = [0.6 	imes n_{eg} - 0.4 	imes n_{t2g}] \Delta_t = [0.6 	imes 2 - 0.4 	imes 3] \Delta_t = 0$. This is correct.$B$. $[Pt(NH_3)ClBr(py)]$ is a square planar complex of type $[Mabcd]$. It shows $3$ geometrical isomers but does not show optical isomerism because square planar complexes are generally achiral. This is incorrect.$C$. $[Fe(CO)_2(NO)_2]$: $Fe$ is $0$ oxidation state $(d^8)$. $NO$ acts as $NO^+$. $EAN = 26 + 2(2) + 2(2) = 36$. It is tetrahedral. This is correct.$D$. $[Co(CO)_4]^-$: $Co$ is $-1$ oxidation state $(d^{10})$. Due to back-bonding from metal to $CO$,the $C-O$ bond order decreases,making the bond length larger than in free $CO$. This is correct.

Which of the following is not correctly matched?

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