Which of the following major product is not c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In option $A$,the reaction of methylenecyclohexane with $HCl$ follows Markovnikov's rule,forming a tertiary carbocation intermediate,which then re

Vedclass · Accepted Answer

$3-$methylcyclohexene + $HCl$ $\rightarrow$ $3-$chloro$-1-$methylcyclohexane

Vedclass · Answer

(C) In option $A$,the reaction of methylenecyclohexane with $HCl$ follows Markovnikov's rule,forming a tertiary carbocation intermediate,which then reacts with $Cl^-$ to give $1-$chloro$-1-$methylcyclohexane. This is correct.In option $B$,the reaction of $1-$methylcyclohexene with $HCl$ also proceeds via a tertiary carbocation intermediate at the $C-1$ position,leading to $1-$chloro$-1-$methylcyclohexane. This is correct.In option $C$,the reaction of $3-$methylcyclohexene with $HCl$ involves the formation of a secondary carbocation. Due to the possibility of carbocation rearrangement (hydride shift),the major product is actually $1-$chloro$-1-$methylcyclohexane,not $3-$chloro$-1-$methylcyclohexane. Therefore,the product shown in option $C$ is incorrect.

Which of the following major product is not correct $:-$

Similar Questions

The product of the reaction is .....

Predict the order of reactivity of the following compounds in $S_N1$ reaction :
$(I)$ $CH_3-CH_2-CH(Br)-CH_3$
$(II)$ $(CH_3)_2CH-CH_2-Br$
$(III)$ $(CH_3)_3CBr$

Reaction of $(R)-2$-butanol with $p$-toluenesulphonyl chloride in pyridine followed by reaction with $LiBr$ gives

In the given reaction
$CH_3-CH(OTs)-CH_2-CH_2-CH(OTs)-CH_3$ $\xrightarrow[(ii) \ KOH]{(i) \ SH^{\ominus} (one \ equivalent)}$ $[X]$
$[X]$ will be :

The major product obtained in the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module