Which of the following molecules/species has | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) To find the number of lone pairs $(LP)$ on the central atom,we use the formula: $LP = \frac{1}{2} (V - N)$,where $V$ is the number of valence elec

Vedclass · Accepted Answer

$XeF_5^+$

Vedclass · Answer

(C) To find the number of lone pairs $(LP)$ on the central atom,we use the formula: $LP = \frac{1}{2} (V - N)$,where $V$ is the number of valence electrons of the central atom and $N$ is the number of bonding electrons (monovalent atoms + charge adjustment).$1. BrF_3$: Central atom $Br$ $(V=7)$. $LP = \frac{1}{2} (7 - 3) = 2 \ LP$.$2. BrF_4^-$: Central atom $Br$ $(V=7+1=8)$. $LP = \frac{1}{2} (8 - 4) = 2 \ LP$.$3. XeF_5^+$: Central atom $Xe$ $(V=8-1=7)$. $LP = \frac{1}{2} (7 - 5) = 1 \ LP$.$4. I_3^-$: Central atom $I$ $(V=7+1=8)$. $LP = \frac{1}{2} (8 - 2) = 3 \ LP$.Comparing the values,$XeF_5^+$ has the minimum number of lone pairs $(1 \ LP)$.

Which of the following molecules/species has the minimum number of lone pairs on its central atom?

Similar Questions

What is the number of lone pairs of electrons on the central atom in $XeF_2, XeF_4$,and $XeF_6$ molecules,respectively?

The structure of $S_2Cl_2$ is analogous to:

The dipole moment $\mu$ of $CH_4$ and $CCl_4$ is $0$. Predict their shapes. Provide the correct shape with reasons.

Which of the following molecules has trigonal planar geometry?

Which of the following is the incorrect order of bond angle?

Vedclass Test Series

Exam Paper Generator

Online Exam Module