In which of the following molecules/ions are | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To determine if all bonds are equal,we examine the molecular geometry and hybridization:$1$. $SiF_4$: $sp^3$ hybridization,tetrahedral geometry. A

Vedclass · Accepted Answer

$ClF_3$

Vedclass · Answer

(A) To determine if all bonds are equal,we examine the molecular geometry and hybridization:$1$. $SiF_4$: $sp^3$ hybridization,tetrahedral geometry. All $Si-F$ bonds are equivalent.$2$. $XeF_4$: $sp^3d^2$ hybridization,square planar geometry. All $Xe-F$ bonds are equivalent.$3$. $BF_4^-$: $sp^3$ hybridization,tetrahedral geometry. All $B-F$ bonds are equivalent.$4$. $ClF_3$: $sp^3d$ hybridization,$T$-shaped geometry. Due to the presence of two lone pairs in the equatorial positions,the axial $Cl-F$ bonds are longer than the equatorial $Cl-F$ bond. Thus,all bonds are not equal.Therefore,the correct option is $A$.

In which of the following molecules/ions are all the bonds not equal?

Similar Questions

Which of the following isomerism is not possible for complexes having molecular formulae?
$(I) Pt(SCN)_2 \cdot 3PEt_3$,$(II) CoBr \cdot SO_4 \cdot 5NH_3$,$(III) FeCl_2 \cdot 6H_2O$

If the harmonic mean between the roots of $(5+\sqrt{2}) x^2-b x+(8+2 \sqrt{5})=0$ is $4$,then the value of $b$ is

In ruby laser,the stimulated emission is due to transition from

In an atom,two electrons move around the nucleus in circular orbits of radii $R$ and $4R$. The ratio of the time taken by them to complete one revolution is:

The transition from the state $n = 4$ to $n = 3$ in a hydrogen-like atom results in ultraviolet radiation. Infrared radiation will be obtained in the transition:

Vedclass Test Series

Exam Paper Generator

Online Exam Module