Which of the following orders cannot be explained by back bonding?
- A$SiH_3OH > CH_3OH$ (Acidic strength)
- B$O(SiH_3)_2 < O(CH_3)_2$ (Lewis basic strength)
- C$BF_3 < BCl_3$ (Lewis acidic strength)
- D$PH_4^+ > NH_3$ (Bond angle)
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Similar Questions
The correct statement regarding the number of lone pairs on the central atom of molecules $SF_4$,$CF_4$,and $XeF_4$ is:
Easy
View SolutionConsider the following reaction:
$2Se_2Cl_2 \to 3Se + SeCl_4$
Choose the $CORRECT$ option regarding the product $SeCl_4$ (referred to as $A$ in the options).
$2Se_2Cl_2 \to 3Se + SeCl_4$
Choose the $CORRECT$ option regarding the product $SeCl_4$ (referred to as $A$ in the options).
Difficult
View SolutionThe shape of the $SF_2Cl_2$ molecule is $...$.
Medium
View SolutionMatch $List-I$ with $List-II$.
$List-I$ (Compound) $List-II$ (Shape) $A$. $BrF_5$ $I$. bent $B$. $[CrF_6]^{3-}$ $II$. square pyramidal $C$. $O_3$ $III$. trigonal bipyramidal $D$. $PCl_5$ $IV$. octahedral
Choose the correct answer from the options given below.
| $List-I$ (Compound) | $List-II$ (Shape) |
|---|---|
| $A$. $BrF_5$ | $I$. bent |
| $B$. $[CrF_6]^{3-}$ | $II$. square pyramidal |
| $C$. $O_3$ | $III$. trigonal bipyramidal |
| $D$. $PCl_5$ | $IV$. octahedral |
Choose the correct answer from the options given below.
How many lone pairs of electrons are present on the chlorine atom in chlorous acid $(HClO_2)$?
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