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(B) The magnetic force on a charged particle is given by $F_m = qvB \sin 	heta$. Since the field is transverse,$	heta = 90^o$,so $F_m = qvB$.The acc

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$H^+$

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(B) The magnetic force on a charged particle is given by $F_m = qvB \sin 	heta$. Since the field is transverse,$	heta = 90^o$,so $F_m = qvB$.The acceleration $a$ is given by $a = \frac{F_m}{m} = \frac{qvB}{m}$.Given that $v$ and $B$ are constant,$a \propto \frac{q}{m}$.Let's calculate the charge-to-mass ratio $(q/m)$ for each particle:$H^+$: $q=1e, m \approx 1u \Rightarrow q/m = 1/1 = 1$$He^{+2}$: $q=2e, m \approx 4u \Rightarrow q/m = 2/4 = 0.5$$Li^+$: $q=1e, m \approx 7u \Rightarrow q/m = 1/7 \approx 0.14$$Be^{+2}$: $q=2e, m \approx 9u \Rightarrow q/m = 2/9 \approx 0.22$Comparing the ratios,$H^+$ has the maximum $q/m$ ratio.Therefore,$H^+$ will experience the maximum acceleration.

Which of the following particles will experience maximum acceleration when projected with the same speed in a transverse magnetic field?

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