Which of the following set of compounds react | vedclass

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(C) $NaHCO_3$ is a mild base and only compounds more acidic than carbonic acid $(H_2CO_3)$ can react with it to evolve $CO_2$ gas.Carboxylic acids are

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$III, IV$ only

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(C) $NaHCO_3$ is a mild base and only compounds more acidic than carbonic acid $(H_2CO_3)$ can react with it to evolve $CO_2$ gas.Carboxylic acids are significantly more acidic than phenols and amines.Compound $(III)$ is benzoic acid and compound $(IV)$ is $p$-nitrobenzoic acid.Both $(III)$ and $(IV)$ are carboxylic acids and are strong enough to react with $NaHCO_3$.Compound $(I)$ is an amine-substituted phenol and compound $(II)$ is phenol; both are less acidic than $H_2CO_3$ and do not react with $NaHCO_3$.Therefore,only $(III)$ and $(IV)$ react with $NaHCO_3$.

Which of the following set of compounds react with $NaHCO_3$?

Similar Questions

Consider the acidity of the following carboxylic acids:
$(I)$ $PhCOOH$
$(II)$ $o-NO_2C_6H_4COOH$
$(III)$ $p-NO_2C_6H_4COOH$
$(IV)$ $m-NO_2C_6H_4COOH$
Which of the following is the correct order of acidity?

$CH_3-CH_2-COOH$ $\xrightarrow{Cl_2/Fe} X$ $\xrightarrow{\text{Alcoholic } KOH} Y$. Compound $Y$ is:

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$II. CF_3COOH$
$III. NO_2CH_2COOH$
$IV. NCCH_2COOH$

What happens when $LiAlH_4$ is added to an ester?

In the following reaction sequence,identify product $Q$ and reagent $R$:

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