Which of the following species is not tetrahe | vedclass

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(B) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the

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$SF_4$

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(B) To determine the geometry,we calculate the hybridization of the central atom using the formula: $H = \frac{1}{2}(V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$1$. For $CH_4$: $H = \frac{1}{2}(4 + 4) = 4$ ($sp^3$ hybridization,tetrahedral).$2$. For $SF_4$: $H = \frac{1}{2}(6 + 4) = 5$ ($sp^3d$ hybridization,see-saw geometry due to one lone pair).$3$. For $\stackrel{+}{N}H_4$: $H = \frac{1}{2}(5 + 4 - 1) = 4$ ($sp^3$ hybridization,tetrahedral).$4$. For $SiCl_4$: $H = \frac{1}{2}(4 + 4) = 4$ ($sp^3$ hybridization,tetrahedral).Thus,$SF_4$ is the only species that is not tetrahedral.

Which of the following species is not tetrahedral?

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