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(A) For $[NiCl_4]^{2-}$:$1$. Oxidation state of $Ni$: $x + 4(-1) = -2 \implies x = +2$.$2$. Coordination number of $Ni$ is $4$.$3$. Electronic configu

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$a, c, d$ and $e$

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(A) For $[NiCl_4]^{2-}$:$1$. Oxidation state of $Ni$: $x + 4(-1) = -2 \implies x = +2$.$2$. Coordination number of $Ni$ is $4$.$3$. Electronic configuration of $Ni^{2+}$ is $[Ar]3d^8$.$4$. $Cl^-$ is a weak field ligand,so no pairing of electrons occurs in the $3d$ orbitals.$5$. The complex undergoes $sp^3$ hybridisation,resulting in a tetrahedral geometry.$6$. Since there are two unpaired electrons,the complex is paramagnetic.$7$. It is a high spin complex because the electrons remain unpaired.Therefore,statements $(a), (c), (d),$ and $(e)$ are true.

Which of the following statements are true about $[NiCl_4]^{2-}$?
$(a)$ The complex has tetrahedral geometry
$(b)$ Coordination number of $Ni$ is $2$ and oxidation state is $+4$
$(c)$ The complex is $sp^3$ hybridised
$(d)$ It is a high spin complex
$(e)$ The complex is paramagnetic

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Which of the following statements are true about $[NiCl_4]^{2-}$?$(a)$ The complex has tetrahedral geometry$(b)$ Coordination number of $Ni$ is $2$ and oxidation state is $+4$$(c)$ The complex is $sp^3$ hybridised$(d)$ It is a high spin complex$(e)$ The complex is paramagnetic