Which of the following statements is correct?

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Question

(A) Let us analyze each option:$A$. $[ZnBr_{4}]^{2-}$: $Br^{-}$ is a weak field ligand and does not cause pairing of electrons. $Zn^{2+}$ has a $d^{10

Vedclass · Accepted Answer

$[ZnBr_{4}]^{2-}$ is tetrahedral.

Vedclass · Answer

(A) Let us analyze each option:$A$. $[ZnBr_{4}]^{2-}$: $Br^{-}$ is a weak field ligand and does not cause pairing of electrons. $Zn^{2+}$ has a $d^{10}$ configuration. The hybridization is $sp^3$,resulting in a tetrahedral geometry. This statement is correct.$B$. $[Ni(NH_{3})_{6}]^{2+}$: $Ni^{2+}$ is $3d^8$. In the presence of $NH_{3}$,it forms an outer orbital complex with $sp^3d^2$ hybridization. It is not an inner orbital complex.$C$. $[Co(NH_{3})_{6}]^{2+}$: $Co^{2+}$ is $3d^7$. In the presence of $NH_{3}$,it forms a low-spin complex,but it is typically oxidized to $Co^{3+}$ in the presence of air/ligands. However,strictly considering $[Co(NH_{3})_{6}]^{2+}$,it has one unpaired electron and is paramagnetic. Note: The question asks for the correct statement,and $A$ is definitively correct.$D$. $[CoBr_{2}(en)_{2}]^{-}$: This complex does not contain ambidentate ligands (like $NO_{2}^{-}$ or $SCN^{-}$),so it cannot exhibit linkage isomerism.Therefore,the most accurate statement is $A$.

List-$I$ (Hybridisation)	List-$II$ (Compound/ion)
$A. sp^3d$	$I. [PtCl_4]^{2-}$
$B. sp^3d^2$	$II. SF_6$
$C. dsp^2$	$III. BCl_3$
$D. dsp^3$	$IV. PCl_5$
	$V. ClF_3$

List-$I$ (Complex)	List-$II$ (Hybridisation of central metal ion)
$A$. $[CoF_6]^{3-}$	$I$. $d^2sp^3$
$B$. $[NiCl_4]^{2-}$	$II$. $sp^3$
$C$. $[Co(NH_3)_6]^{3+}$	$III$. $sp^3d^2$
$D$. $[Ni(CN)_4]^{2-}$	$IV$. $dsp^2$

Similar Questions

Match the following:
List-$I$ (Hybridisation) List-$II$ (Compound/ion)
$A. sp^3d$ $I. [PtCl_4]^{2-}$
$B. sp^3d^2$ $II. SF_6$
$C. dsp^2$ $III. BCl_3$
$D. dsp^3$ $IV. PCl_5$
$V. ClF_3$

The correct match is:

$EDTA^{4-}$ is the ethylenediaminetetraacetate ion. The total number of $N-Co-O$ bond angles in the $[Co(EDTA)]^{-}$ complex ion is:

Which of the following is an incorrect pair?

Match List-$I$ with List-$II$.
List-$I$ (Complex) List-$II$ (Hybridisation of central metal ion)
$A$. $[CoF_6]^{3-}$ $I$. $d^2sp^3$
$B$. $[NiCl_4]^{2-}$ $II$. $sp^3$
$C$. $[Co(NH_3)_6]^{3+}$ $III$. $sp^3d^2$
$D$. $[Ni(CN)_4]^{2-}$ $IV$. $dsp^2$
Choose the correct answer from the options given below:

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