Which of the following will form two isomers | vedclass

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(A) For a compound to exhibit geometrical isomerism ($E$ and $Z$ isomers) upon reaction with semicarbazide,the resulting semicarbazone must have two d

Vedclass · Accepted Answer

Benzaldehyde

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(A) For a compound to exhibit geometrical isomerism ($E$ and $Z$ isomers) upon reaction with semicarbazide,the resulting semicarbazone must have two different groups attached to the carbon atom of the $C=N$ bond.$Benzaldehyde$ $(C_6H_5CHO)$ reacts with semicarbazide to form benzaldehyde semicarbazone $(C_6H_5CH=NNHCONH_2)$.In this product,the carbon atom is bonded to a phenyl group $(-C_6H_5)$ and a hydrogen atom $(-H)$,which are different.Thus,it can exist in two geometrical isomeric forms ($E$ and $Z$).Acetone,benzoquinone,and benzophenone do not show this specific type of isomerism with semicarbazide because they either have identical groups on the carbon atom or are constrained differently.

Which of the following will form two isomers with semicarbazide?

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