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Question

(D) Step $1$: Analyze structure $P = OHC-CH_2-CH=CH-CH_2-CHO$. It contains two aldehyde groups $(-CHO)$, so it is a dialdehyde (hex$-3-$enedial).Step

Vedclass · Accepted Answer

Both $(B)$ and $(C)$ are correct.

Vedclass · Answer

(D) Step $1$: Analyze structure $P = OHC-CH_2-CH=CH-CH_2-CHO$. It contains two aldehyde groups $(-CHO)$, so it is a dialdehyde (hex$-3-$enedial).Step $2$: Analyze structure $Q = HO-CH_2-CH_2-CH_2-CH_2-CH_2-CH_2-OH$. It contains two hydroxyl groups $(-OH)$, so it is a diol (hexane$-1,6-$diol).Step $3$: Analyze structure $R = HO-CH_2-CH_2-CH=CH-CH_2-CHO$. It contains both a hydroxyl group $(-OH)$ and an aldehyde group $(-CHO)$, making it a hydroxy aldehyde.Step $4$: Since statements $(B)$ and $(C)$ are both correct, the correct option is $(D)$.

Based on the structures $P$, $Q$, and $R$ defined as $P = OHC-CH_2-CH=CH-CH_2-CHO$, $Q = HO-CH_2-CH_2-CH_2-CH_2-CH_2-CH_2-OH$, and $R = HO-CH_2-CH_2-CH=CH-CH_2-CHO$, which of the following statements is correct?

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