Which one of the following complexes is an ou | vedclass

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(D) An outer orbital complex uses the outer $d$-orbitals (e.g.,$4d$) for hybridization,typically $sp^3d^2$.$1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$

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$[Ni(NH_3)_6]^{2+}$

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(D) An outer orbital complex uses the outer $d$-orbitals (e.g.,$4d$) for hybridization,typically $sp^3d^2$.$1$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$2$. $[Mn(CN)_6]^{4-}$: $Mn^{2+}$ is $3d^5$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$3$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand for $Co^{3+}$,causing pairing. Hybridization is $d^2sp^3$ (inner orbital).$4$. $[Ni(NH_3)_6]^{2+}$: $Ni^{2+}$ is $3d^8$. $NH_3$ is a weak field ligand relative to $Ni^{2+}$. Hybridization is $sp^3d^2$ (outer orbital).Thus,$[Ni(NH_3)_6]^{2+}$ is an outer orbital complex.

List-$I$ (Compound)	List-$II$ (Hybridization of Central atom)
$A. [Ni(NH_3)_6]^{2+}$	$1. sp^3$
$B. [PtCl_4]^{2-}$	$2. sp^3d^2$
$C. [Ni(CO)_4]$	$3. dsp^2$
$D. [Co(ox)_3]^{3-}$	$4. d^2sp^3$

Which one of the following complexes is an outer orbital complex?
Atomic no.: $Mn = 25, Fe = 26, Co = 27, Ni = 28$

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Which one of the following complexes is an outer orbital complex?Atomic no.: $Mn = 25, Fe = 26, Co = 27, Ni = 28$